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0.5x^2-5x-1500=0
a = 0.5; b = -5; c = -1500;
Δ = b2-4ac
Δ = -52-4·0.5·(-1500)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-55}{2*0.5}=\frac{-50}{1} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+55}{2*0.5}=\frac{60}{1} =60 $
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